Step 1 :First, calculate the proportions of female students who took the biology and calculus AB exams. The proportion of female students who took the biology exam is \( \frac{84801}{144470} = 0.5869799958468886 \) and the proportion of female students who took the calculus AB exam is \( \frac{124859}{213697} = 0.5842805467554528 \).
Step 2 :Next, calculate the standard error of the difference in proportions. The standard error is \( \sqrt{\left(\frac{0.5869799958468886 \times (1 - 0.5869799958468886)}{144470}\right) + \left(\frac{0.5842805467554528 \times (1 - 0.5842805467554528)}{213697}\right)} = 0.001677717719069156 \).
Step 3 :Then, calculate the confidence interval. The z-score for a 95% confidence level is 1.96. The lower limit of the confidence interval is \( (0.5869799958468886 - 0.5842805467554528) - 1.96 \times 0.001677717719069156 = -0.0005888776379397221 \) and the upper limit of the confidence interval is \( (0.5869799958468886 - 0.5842805467554528) + 1.96 \times 0.001677717719069156 = 0.005987775820811369 \).
Step 4 :Finally, the difference in the proportion of female students taking the biology exam and female students taking the calculus AB exam, with a 95% confidence level, is between -0.0006 and 0.0060. In other words, we can be 95% confident that the true difference in proportions is between these two values. This is represented as \(\boxed{[-0.0006, 0.0060]}\).