Step 1 :The functions $f$ and $g$ are defined as follows: $f(x)=\frac{x-3}{x^{2}-10 x+21}$ and $g(x)=\frac{x^{2}}{x-9}$.
Step 2 :The domain of a function is the set of all possible input values (often the 'x' variable), which produce a valid output from a particular function.
Step 3 :For these functions, we need to find the values of x for which the functions are defined.
Step 4 :For the function $f(x)$, the denominator cannot be equal to zero because division by zero is undefined in mathematics. Therefore, we need to find the values of x that make the denominator zero and exclude them from the domain.
Step 5 :For the function $g(x)$, the denominator also cannot be zero. So, we need to find the value of x that makes the denominator zero and exclude it from the domain.
Step 6 :The solutions for the denominators of the functions $f(x)$ and $g(x)$ are $x = 3, 7$ and $x = 9$ respectively. These are the values that make the denominators zero and hence, they should be excluded from the domain of the functions.
Step 7 :Therefore, the domain of the function $f(x)$ is all real numbers except 3 and 7. The domain of the function $g(x)$ is all real numbers except 9.
Step 8 :Final Answer: The domain of the function $f(x)$ is \(\boxed{\mathbb{R} \setminus \{3, 7\}}\) and the domain of the function $g(x)$ is \(\boxed{\mathbb{R} \setminus \{9\}}\).