Complete the sentence below. The maximum value of $y=\sin x, 0 \leq x \leq 2 \pi$, is and occurs at $x=$ The maximum value of $y=\sin x, 0 \leq x \leq 2 \pi$, is $\square$ and occurs at $x=$ (Simplify your answers. Type exact answers, using $\pi$ as needed.)

Step 1 ：The function \(y=\sin x\) is a periodic function with period \(2\pi\). It reaches its maximum value of 1 at \(x=\frac{\pi}{2}\) within the interval \(0 \leq x \leq 2 \pi\).

Step 2 ：Final Answer: The maximum value of \(y=\sin x, 0 \leq x \leq 2 \pi\), is \(\boxed{1}\) and occurs at \(x=\boxed{\frac{\pi}{2}}\).