Step 1 :The problem is asking for the probability that the sample mean is less than 146.97 liters. This is a problem of normal distribution.
Step 2 :We can use the z-score formula to calculate the z-score for 146.97 liters, and then use the standard normal distribution to find the probability.
Step 3 :The z-score formula is: \(z = \frac{X - \mu}{\sigma / \sqrt{n}}\) where: \(X\) is the value we are interested in (146.97 liters), \(\mu\) is the mean (153 liters), \(\sigma\) is the standard deviation (27 liters), and \(n\) is the sample size (90).
Step 4 :After calculating the z-score, we can use the standard normal distribution to find the probability that the z-score is less than the calculated value. This will give us the probability that the sample mean is less than 146.97 liters.
Step 5 :Final Answer: The probability that the sample mean would be less than 146.97 liters is \(\boxed{0.0171}\).