Step 1 :This is a geometric series where each term is 4 times the previous term. The first term is 1 and the common ratio is 4. The series has 8 terms.
Step 2 :In general, the nth term of a geometric series with first term a and common ratio r is given by a*r^(n-1).
Step 3 :So, we can express this series using summation notation as the sum from n=1 to 8 of 4^(n-1).
Step 4 :Final Answer: The geometric sum can be expressed using summation notation as \(\boxed{\sum_{n=1}^{8} 4^{n-1}}\)