Step 1 :Given that \(\sin \theta = \frac{1}{\sqrt{5}}\)
Step 2 :Use the Pythagorean identity \(\sin^2 \theta + \cos^2 \theta = 1\) to find \(\cos \theta\)
Step 3 :\(\cos \theta = \sqrt{1 - \sin^2 \theta} = \sqrt{1 - \left(\frac{1}{\sqrt{5}}\right)^2} = \frac{2}{\sqrt{5}}\)
Step 4 :Use the definitions of the other trigonometric functions in terms of \(\sin \theta\) and \(\cos \theta\) to find their values
Step 5 :\(\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{\frac{1}{\sqrt{5}}}{\frac{2}{\sqrt{5}}} = \frac{1}{2}\)
Step 6 :\(\csc \theta = \frac{1}{\sin \theta} = \sqrt{5}\)
Step 7 :\(\sec \theta = \frac{1}{\cos \theta} = \frac{\sqrt{5}}{2}\)
Step 8 :\(\cot \theta = \frac{1}{\tan \theta} = 2\)
Step 9 :Final Answer: \(\boxed{\sin \theta = \frac{1}{\sqrt{5}}, \cos \theta = \frac{2}{\sqrt{5}}, \tan \theta = \frac{1}{2}, \csc \theta = \sqrt{5}, \sec \theta = \frac{\sqrt{5}}{2}, \cot \theta = 2}\)