Problem
find out the value of \( x: x^{\wedge} 2-1=n d \) out the value of \( x: x^{\wedge} 2-1=0 \) Solving Steps Answer: +1 find out the value of \( x \) : \( x^{\wedge} 2-1=0 \) find out the value!! \( x^{\wedge} 2-1=0+1 \) find out the value of \( x \) : \( x^{\wedge} 2-1=0 \) find out the value of \( x \) : \( x^{\wedge} 2-1=0 \) (1) Add 1 to both sides of the equation: \( x^{\wedge} 2=1 \) (2) Take the square root of both sides: \( x=\ddagger / 1 \) (3) Take the square root of both sides: \( x=\ddagger / 1 \) (4) Take the square root of both sides: \( x=\ddagger / 1 \)
Solution
Step 1 ：To solve the quadratic equation x^2-1=0:
Step 2 ：Add 1 to both sides of the equation: x^2=1
Step 3 ：Take the square root of both sides: x=1 or x=-1
