Step 1 :We are given that \(\cos(A) = -\frac{21}{29}\) and that \(A\) is in quadrant 3.
Step 2 :We are asked to find \(\cos(2A)\).
Step 3 :We know that the formula for \(\cos(2A)\) is \(2\cos^2(A) - 1\).
Step 4 :Substituting \(\cos(A) = -\frac{21}{29}\) into the formula, we get \(\cos(2A) = 2(-\frac{21}{29})^2 - 1\).
Step 5 :Solving this, we find that \(\cos(2A) = 0.04875148632580273\).
Step 6 :Since \(A\) is in quadrant 3, \(\cos(2A)\) will also be negative.
Step 7 :So, the final answer is \(\boxed{0.04875148632580273}\).