Problem

Bo is flying a kite, holding his hands a distance of 3.5 feet above the ground and letting all the kite's string play out. He measures the angle of elevation from his hand to the kite to be $29^{\circ}$. If the string from the kite to his hand is 110 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.

Solution

Step 1 :Find the height of the kite above Bo's hand using sine function: height_above_hand = \(\sin(29^\circ) \times 110\)

Step 2 :Add the height of Bo's hand above the ground to find the total height of the kite above the ground: total_height = height_above_hand + 3.5

Step 3 :Calculate the height_above_hand: \(\sin(29^\circ) \times 110 \approx 53.3\)

Step 4 :Calculate the total_height: \(53.3 + 3.5 = 56.8\)

Step 5 :\(\boxed{56.8}\) feet above the ground

From Solvely APP
Source: https://solvelyapp.com/problems/8754/

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