Problem

Find the value of each trigonometric ratio. 5) $\sin Z$ A) $\frac{12}{5}$ B) $\frac{5}{13}$ C) $\frac{13}{12}$ D) $\frac{5}{12}$

Solution

Step 1 :\(\sin^2 Z + \cos^2 Z = 1\)

Step 2 :\(\sin^2 Z = 1 - \cos^2 Z\)

Step 3 :\(\sin^2 Z = 1 - \left(\frac{5}{13}\right)^2\)

Step 4 :\(\sin^2 Z = 1 - \frac{25}{169}\)

Step 5 :\(\sin^2 Z = \frac{144}{169}\)

Step 6 :\(\sin Z = \pm\frac{12}{13}\)

Step 7 :\boxed{\frac{12}{13}}

From Solvely APP
Source: https://solvelyapp.com/problems/8737/

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