Step 1 :The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. This means that the probability of a passenger waiting for any particular amount of time between 0 and 5 minutes is the same.
Step 2 :Therefore, the probability of a passenger waiting less than 1.75 minutes is simply the ratio of 1.75 minutes to the total time interval of 5 minutes.
Step 3 :Let's calculate this ratio: \(\frac{1.75}{5}\)
Step 4 :The result is 0.35
Step 5 :Final Answer: The probability that a randomly selected passenger has a waiting time less than 1.75 minutes is \(\boxed{0.35}\)