Problem

Determine $\int\left[\left(\frac{1}{2}\right)^{x}+x^{1 / 2}\right] d x$ A. $\frac{1}{\ln (2) \cdot 2^{x}}+\frac{2}{3} x^{3 / 2}+C$ B. $\frac{1}{\ln (1 / 2)}\left(\frac{1}{2}\right)^{x}+\frac{2}{3} x^{3 / 2}+C$ $c-\frac{1}{\ln (x) \cdot 2^{x}}+\frac{2}{3} x^{3 / 2}+C$ D. $\frac{1}{x+1}\left(\frac{1}{2}\right)^{x+1}+\frac{2}{3} x^{3 / 2}+C$ E. $-\frac{1}{\ln (2) \cdot 2^{x}}+\frac{2}{3} x^{5 / 2}+C$

Solution

Step 1 :The integral is a sum of two terms, so we can integrate each term separately.

Step 2 :The first term is a simple exponential function, and the second term is a power function.

Step 3 :The integral of an exponential function is the same function divided by the natural logarithm of its base.

Step 4 :The integral of a power function is the function with its exponent increased by 1, divided by the new exponent.

Step 5 :Therefore, the integral of the function is \(\frac{1}{\ln (2) \cdot 2^{x}}+\frac{2}{3} x^{3 / 2}+C\).

Step 6 :Final Answer: \(\boxed{\frac{1}{\ln (2) \cdot 2^{x}}+\frac{2}{3} x^{3 / 2}+C}\)

From Solvely APP
Source: https://solvelyapp.com/problems/8685/

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