Solve for $17^{x}$ if $\log _{3}\left((-26)+17^{x}\right)=3$. \[ 17^{x}= \]

Step 1 ：First, we rewrite the equation using the property of logarithms, which states that \(\log _{b} a^{n}=n \log _{b} a\). So, we have \(\log _{3}(-26+17^{x})=3\).

Step 2 ：Next, we convert the logarithmic equation to an exponential equation. This gives us \(3^{3}=-26+17^{x}\).

Step 3 ：Solving for \(17^{x}\), we get \(17^{x}=3^{3}+26\).

Step 4 ：Substituting the values, we get \(17^{x}=27+26\).

Step 5 ：Finally, we simplify to get \(17^{x}=\boxed{53}\).