Solve the system by the elimination/addition method \[ \begin{array}{l} 3 x+2 y=10 \\ -4 x-3 y=-13 \end{array} \]

Step 1 ：\(\begin{array}{l} 3x+2y=10 \\ -4x-3y=-13 \end{array}\)

Step 2 ：\(\begin{array}{l} 12x+8y=40 \\ -12x-9y=-39 \end{array}\)

Step 3 ：Add the two equations: \(-y=1\)

Step 4 ：\(\boxed{y=-1}\)

Step 5 ：Substitute y into the first equation: \(3x+2(-1)=10\)

Step 6 ：\(3x-2=10\)

Step 7 ：\(\boxed{x=4}\)

Step 8 ：Final Answer: \(\boxed{x=4, y=-1}\)