Step 1 :The given function is a quadratic function of the form \(f(x) = ax^2 + bx + c\), where \(a = -1\), \(b = 4\), and \(c = -6\).
Step 2 :Since the coefficient of \(x^2\) (i.e., \(a\)) is negative, the parabola opens downwards. This means the function has a maximum value.
Step 3 :The maximum or minimum value of a quadratic function \(f(x) = ax^2 + bx + c\) occurs at \(x = -b/(2a)\).
Step 4 :The maximum or minimum value of the function is \(f(-b/(2a))\).
Step 5 :Let's calculate these values.
Step 6 :\(a = -1\), \(b = 4\), \(c = -6\)
Step 7 :\(x_{vertex} = 2.0\)
Step 8 :\(max_{value} = -2.0\)
Step 9 :The x-coordinate of the vertex (where the maximum value occurs) is 2.0 and the maximum value of the function is -2.0. These are the answers to the questions.
Step 10 :Final Answer: The function has a maximum value. The maximum value occurs at \(x = 2.0\). The maximum value of the function is \(\boxed{-2.0}\).