A bike accelerates uniformly from rest to a speed of \( 5 \mathrm{~m} / \mathrm{s} \) over a distance of \( 36 \mathrm{~m} \). Determine the acceleration of the bike. (m/s \( \mathrm{s}^{2} \) unit

Step 1 ：Step 1: Rearrange the equation: \(v^{2} = u^{2} + 2as\) to solve for acceleration. Given that \(v = 5 \mathrm{~m/s}\), \(u = 0 \mathrm{~m/s}\) (from rest), and \(s = 36 \mathrm{~m}\), we want to find \(a\).

Step 2 ：Step 2: Substitute the given values into the equation: \(5^{2} = 0^{2} + 2a(36)\).

Step 3 ：Step 3: Solve for \(a\): \(a = \frac{5^{2}}{2 \times 36}\)