In the game of roulette, a steel ball is rolled onto a wheel that contains 18 red, 18 black, and 2 green slots. If the ball is rolled 36 times, find the probability of the following events. A. The ball falls into the green slots 5 or more times. Probability $=$ B. The ball does not fall into any green slots. Probability $=$ C. The ball falls into black slots 12 or more times. Probability $=$ D. The ball falls into red slots 12 or fewer times. Probability $=$

Step 1 ：In the game of roulette, a steel ball is rolled onto a wheel that contains 18 red, 18 black, and 2 green slots. If the ball is rolled 36 times, we are asked to find the probability of the ball falling into the green slots 5 or more times.

Step 2 ：The probability of the ball falling into a green slot in a single roll is \(\frac{2}{38}\), since there are 2 green slots out of a total of 38 slots.

Step 3 ：This is a binomial probability problem, where the number of trials is 36, the number of successful trials is 5 or more, and the probability of success on a single trial is \(\frac{2}{38}\).

Step 4 ：The binomial probability formula is: \(P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))\), where \(P(X=k)\) is the probability of \(k\) successes in \(n\) trials, \(C(n, k)\) is the number of combinations of \(n\) items taken \(k\) at a time, \(p\) is the probability of success on a single trial, \(n\) is the number of trials, and \(k\) is the number of successful trials.

Step 5 ：However, since we want the probability of 5 or more successes, we need to sum up the probabilities for 5, 6, 7, ..., 36 successes.

Step 6 ：Using the binomial probability formula and summing up the probabilities for 5 to 36 successes, we get a probability of approximately 0.039.

Step 7 ：Final Answer: The probability that the ball falls into the green slots 5 or more times is approximately \(\boxed{0.039}\).