The mean score on a driving exam for a group of driver's education students is 76 points, with a standard deviation of 5 points. Apply Chebychev's Theorem to the data using {k}=2 Interpret the results. At least % of the exam scores fall between and (Simplify your answers.)

Step 1 ：Given that the mean score on a driving exam for a group of driver's education students is 76 points, with a standard deviation of 5 points. We are asked to apply Chebychev's Theorem to the data using {k}=2 and interpret the results.

Step 2 ：Chebyshev's theorem states that at least \(1 - \frac{1}{k^2}\) of the data lies within k standard deviations of the mean for any k > 1. In this case, k = 2.

Step 3 ：So, we need to calculate \(1 - \frac{1}{k^2}\), which will give us the percentage of scores that fall within 2 standard deviations of the mean.

Step 4 ：Substituting k = 2 into the formula, we get \(1 - \frac{1}{2^2} = 1 - \frac{1}{4} = 0.75\) or 75%.

Step 5 ：We also need to calculate the range of scores that fall within 2 standard deviations of the mean, which is mean - 2*standard deviation and mean + 2*standard deviation.

Step 6 ：Substituting the given values into the formula, we get lower bound = 76 - 2*5 = 66 and upper bound = 76 + 2*5 = 86.

Step 7 ：\(\boxed{\text{Final Answer: At least 75% of the exam scores fall between 66 and 86.}}\)