Step 1 :Given the trigonometric equation \(1 - \sin 2 \theta = 3 \sin 2 \theta\).
Step 2 :Rearrange the equation to isolate the trigonometric function, we get \(4 \sin 2 \theta = 1\).
Step 3 :Divide both sides by 4, we get \(\sin 2 \theta = \frac{1}{4}\).
Step 4 :Use the inverse sine function to find the value of \(2 \theta\), we get \(2 \theta = \sin^{-1}(\frac{1}{4})\).
Step 5 :Solving for \(\theta\), we get \(\theta = \frac{\sin^{-1}(\frac{1}{4})}{2}\).
Step 6 :Converting to degrees, we get two solutions \(\theta = 7.2^\circ\) and \(\theta = 82.8^\circ\).
Step 7 :Since the sine function has a period of 180 degrees, the general solutions are \(\theta = 7.2^\circ + 180n\) and \(\theta = 82.8^\circ + 180n\), where n is any integer.
Step 8 :\(\boxed{\text{Final Answer: The solutions to the equation are } \{7.2^\circ + 180^\circ n, 82.8^\circ + 180^\circ n\}, \text{ where n is any integer.}}\)