What is the c-value needed to complete the square for the following quadratic: $x^{2}-5 x-12=0$ ? $-5$ $-5 / 2$ 12 $25 / 4$

Step 1 ：Given the quadratic equation \(x^{2}-5 x-12=0\)

Step 2 ：The equation is in the form \(x^{2}+bx+c=0\)

Step 3 ：To complete the square, we need to find the value of \(c\) such that the equation can be written in the form \((x-d)^{2}=0\)

Step 4 ：This is achieved when \(c = (b/2)^{2}\)

Step 5 ：In this case, \(b = -5\)

Step 6 ：So, we need to calculate \((-5/2)^{2}\)

Step 7 ：\(b = -5\)

Step 8 ：\(c = 6.25\)

Step 9 ：Final Answer: The c-value needed to complete the square for the quadratic \(x^{2}-5 x-12=0\) is \(\boxed{6.25}\)