Step 1 :First, we need to find the period of the function. The period of a function of the form \(y = a \cos (bx)\) or \(y = a \sin (bx)\) is given by \(\frac{2\pi}{|b|}\).
Step 2 :In this case, \(b = 5\), so the period of the function \(y = -3 \cos 5x\) is \(\frac{2\pi}{5}\).
Step 3 :Next, we need to find the amplitude of the function. The amplitude of a function of the form \(y = a \cos (bx)\) or \(y = a \sin (bx)\) is given by \(|a|\).
Step 4 :In this case, \(a = -3\), so the amplitude of the function \(y = -3 \cos 5x\) is \(3\).
Step 5 :Finally, we need to graph the function over a two-period interval. The function \(y = -3 \cos 5x\) is a cosine function with a period of \(\frac{2\pi}{5}\) and an amplitude of 3, and it is reflected about the x-axis because the coefficient of the cosine function is negative.
Step 6 :The graph of the function \(y = -3 \cos 5x\) over a two-period interval is shown below:
Step 7 :\[\text{Graph of } y = -3 \cos 5x\]
Step 8 :\[\text{The period of the function } y = -3 \cos 5x \text{ is } \boxed{\frac{2\pi}{5}}.\]
Step 9 :\[\text{The amplitude of the function } y = -3 \cos 5x \text{ is } \boxed{3}.\]