- Of the cars on a used car lot, $70 \%$ have air conditioning $(A C)$ and $40 \%$ have a $C D$ player (CD). $20 \%$ of the cars have both. What is the probability that a car has a CD player, given that it has AC?

Step 1 ：Given probabilities: P(AC) = 0.7, P(CD) = 0.4, P(CD ∩ AC) = 0.2

Step 2 ：Use the conditional probability formula: P(CD | AC) = \(\frac{P(CD \cap AC)}{P(AC)}\)

Step 3 ：Plug in the values: P(CD | AC) = \(\frac{0.2}{0.7}\)

Step 4 ：Calculate the probability: P(CD | AC) ≈ 0.286

Step 5 ：\(\boxed{0.286}\) or \(\boxed{28.6\%}\) is the probability that a car has a CD player, given that it has AC