Problem

- Of the cars on a used car lot, $70 \%$ have air conditioning $(A C)$ and $40 \%$ have a $C D$ player (CD). $20 \%$ of the cars have both. What is the probability that a car has a CD player, given that it has AC?

Solution

Step 1 :Given probabilities: P(AC) = 0.7, P(CD) = 0.4, P(CD ∩ AC) = 0.2

Step 2 :Use the conditional probability formula: P(CD | AC) = \(\frac{P(CD \cap AC)}{P(AC)}\)

Step 3 :Plug in the values: P(CD | AC) = \(\frac{0.2}{0.7}\)

Step 4 :Calculate the probability: P(CD | AC) ≈ 0.286

Step 5 :\(\boxed{0.286}\) or \(\boxed{28.6\%}\) is the probability that a car has a CD player, given that it has AC

From Solvely APP
Source: https://solvelyapp.com/problems/8364/

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