Problem
In a certain Algebra 2 class of 24 students, 6 of them play basketball and 16 of them play baseball. There are 6 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Solution
Step 1 ：Let x be the number of students who play both sports. Then, we have the equation: \(6 + 16 - x = 18\)
Step 2 ：Solving for x, we get \(x = 4\). So, the probability is \(\frac{4}{24} = \boxed{\frac{1}{6}}\)
