Problem
Use the balanced equation to solve the problem. \[ 2 \mathrm{Al}_{2} \mathrm{O}_{3} \rightarrow 4 \mathrm{Al}+3 \mathrm{O}_{2} \] \( 2.80 \mathrm{~mol} \) of aluminum are produced. How many moles of \( \mathrm{O}_{2} \) are made? \( \mathrm{mol} \)
Solution
Step 1 ：\( \frac{3 \mathrm{O}_{2}}{4 \mathrm{Al}}=\frac{x \mathrm{mol}}{2.80 \mathrm{~mol}} \)
Step 2 ：x = \frac{3 \mathrm{O}_{2} \cdot 2.80 \mathrm{~mol}}{4 \mathrm{Al}}
Step 3 ：x = 2.10 \mathrm{mol}
