Elizabeth brought a box of donuts to share. There are two-dozen (24) donuts in the box, all identical in size, shape, and color. Four are jelly-filled, 6 are lemon-filled, and 14 are custard-filled. You randomly select one donut, eat it, and select another donut. Find the probability of selecting a lemon-filled donut followed by a jelly-filled donut. (Type an integer or a simplified fraction.)

Step 1 ：Elizabeth brought a box of donuts to share. There are two-dozen (24) donuts in the box, all identical in size, shape, and color. Four are jelly-filled, 6 are lemon-filled, and 14 are custard-filled. You randomly select one donut, eat it, and select another donut. We are to find the probability of selecting a lemon-filled donut followed by a jelly-filled donut.

Step 2 ：The probability of an event is calculated by dividing the number of ways the event can occur by the total number of outcomes. In this case, the event is selecting a lemon-filled donut followed by a jelly-filled donut.

Step 3 ：The total number of outcomes is the total number of donuts, which is 24 initially and 23 after one donut is eaten.

Step 4 ：The number of ways to select a lemon-filled donut is 6, and the number of ways to select a jelly-filled donut after eating a lemon-filled donut is 4.

Step 5 ：So, the probability of this event is \(\frac{6}{24}\) * \(\frac{4}{23}\).

Step 6 ：Final Answer: The probability of selecting a lemon-filled donut followed by a jelly-filled donut is \(\boxed{\frac{1}{23}}\).