Problem

If you are dealt 3 cards from a shuffled deck of 52 cards, find the probability of getting one queen and two kings. The probability is (Round to six decimal places as needed.)

Solution

Step 1 :We are given a shuffled deck of 52 cards and we are to find the probability of getting one queen and two kings when dealt 3 cards.

Step 2 :The total number of ways to draw 3 cards from a deck of 52 is given by the combination formula \(C(n, k) = \frac{n!}{k!(n-k)!}\), where n is the total number of items, k is the number of items to choose, and '!' denotes factorial. In this case, n=52 and k=3, which gives us a total of 22100 ways.

Step 3 :The number of ways to draw one queen from four available is \(C(4, 1)\), which gives us 4 ways.

Step 4 :The number of ways to draw two kings from four available is \(C(4, 2)\), which gives us 6 ways.

Step 5 :The probability of both events occurring is the product of their individual probabilities. Therefore, the probability of drawing one queen and two kings is \(\frac{C(4, 1) * C(4, 2)}{C(52, 3)}\).

Step 6 :Substituting the values we have, the probability is approximately 0.0010859728506787331.

Step 7 :Final Answer: The probability of getting one queen and two kings when dealt 3 cards from a shuffled deck of 52 cards is approximately \(\boxed{0.001086}\).

From Solvely APP
Source: https://solvelyapp.com/problems/8306/

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