Step 1 :The problem is asking for the probability of drawing a nine and a king from a standard 52-card deck. It's not specified whether we are replacing the card back into the deck after each draw (with replacement) or not (without replacement).
Step 2 :Assuming we are not replacing the card (without replacement), the probability of drawing a nine and then a king would be calculated as follows:
Step 3 :There are 4 nines and 4 kings in a standard 52-card deck. The probability of drawing a nine first is \(\frac{4}{52}\). After drawing a nine, there are now 51 cards left in the deck. The probability of drawing a king next is \(\frac{4}{51}\).
Step 4 :The total probability of this happening is the product of the two probabilities, which is approximately 0.006033182503770739.
Step 5 :Final Answer: The probability of being dealt a nine and a king from a standard 52-card deck, without replacement, is approximately \(\boxed{0.006}\).