Problem

Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find the value. \[ f(x)=3 x^{2}+18 x-1 \] Does the quadratic function $\mathrm{f}$ have a minimum value or a maximum value? The function $f$ has a minimum value. The function $\mathrm{f}$ has a maximum value. What is this minimum or maximum value? (Simplify your answer.)

Solution

Step 1 :The given function is a quadratic function of the form \(f(x) = ax^2 + bx + c\).

Step 2 :The coefficient of \(x^2\) is positive, so the parabola opens upwards. This means that the function has a minimum value.

Step 3 :The minimum or maximum value of a quadratic function \(f(x) = ax^2 + bx + c\) is given by \(f(-\frac{b}{2a})\).

Step 4 :So, we need to substitute \(x = -\frac{b}{2a}\) into the function to find the minimum value.

Step 5 :Given that \(a = 3\), \(b = 18\), and \(c = -1\), we find that \(x = -3.0\).

Step 6 :Substituting \(x = -3.0\) into the function, we find that the minimum value is \(-28.0\).

Step 7 :Final Answer: The minimum value of the function is \(\boxed{-28}\).

From Solvely APP
Source: https://solvelyapp.com/problems/8274/

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