Step 1 :Define the profit function, \(P(x)\), as the difference between the revenue function, \(R(x)\), and the cost function, \(C(x)\). That is, \(P(x) = R(x) - C(x)\).
Step 2 :Find the derivative of the profit function, \(P'(x)\), to find the critical points of the profit function.
Step 3 :Set the derivative equal to zero and solve for \(x\) to find the critical points. The critical points are \(x = 1 - \sqrt{30}/3\) and \(x = 1 + \sqrt{30}/3\).
Step 4 :Evaluate the profit function at these critical points and at the endpoints of the domain (if any) to find the maximum profit.
Step 5 :The maximum profit is \(- (1 + \sqrt{30}/3)^3 + 6 + 7\sqrt{30}/3 + 3(1 + \sqrt{30}/3)^2\).
Step 6 :The production level that yields the maximum profit is \(x = 1 + \sqrt{30}/3\).
Step 7 :Final Answer: The production level for the maximum profit is about \(\boxed{3}\) units.