Find $\int \frac{x-1}{x^{2}} d x$

Step 1 ：Given the integral problem \(\int \frac{x-1}{x^{2}} dx\)

Step 2 ：We can rewrite the integrand as \(\frac{x}{x^{2}} - \frac{1}{x^{2}}\)

Step 3 ：Now, we can integrate each term separately

Step 4 ：The integral of the function \(\frac{x-1}{x^{2}}\) is \(\log(x) + \frac{1}{x} + C\), where \(C\) is the constant of integration

Step 5 ：Final Answer: \(\boxed{\log(x) + \frac{1}{x} + C}\)