Select the correct answer. Solve $-36 \frac{4}{9}-\left(-10 \frac{2}{9}\right)-\left(18 \frac{2}{9}\right)$ A. $-44 \frac{4}{9}$ B. -28 C. $8 \frac{4}{9}$ D. $64 \frac{8}{9}$

Step 1 ：Convert each mixed number into an improper fraction: \(-36 \frac{4}{9} = -\frac{320}{9}\), \(-10 \frac{2}{9} = -\frac{88}{9}\), and \(18 \frac{2}{9} = \frac{164}{9}\)

Step 2 ：Subtract the fractions: \(-\frac{320}{9} - (-\frac{88}{9}) - \frac{164}{9} = -\frac{396}{9}\)

Step 3 ：Convert the result back into a mixed number: \(-\frac{396}{9} = -44\)

Step 4 ：The result of the subtraction is -44, which is a whole number. Therefore, the fraction part is 0

Step 5 ：Final Answer: \(\boxed{-44}\)