Problem

Question 4 Given: $g(n)=n^{3}+5 n$ and $h(n)=3 n+3$ Find: $h(g(n+1))$ $4 n^{3}+12 n^{2}-3 n+14$ $3 n^{3}+9 n^{2}+24 n+21$ $6 n^{2}-4 n+6$ There is no correct answer given. $-9 n^{3}-24 n+18$

Solution

Step 1 :Given the functions $g(n)=n^{3}+5 n$ and $h(n)=3 n+3$, we are asked to find the value of $h(g(n+1))$.

Step 2 :First, we need to find the value of $g(n+1)$.

Step 3 :Substituting $n+1$ into $g(n)$, we get $g(n+1) = (n+1)^{3}+5(n+1)$.

Step 4 :Next, we substitute this value into $h(n)$ to get $h(g(n+1)) = 3g(n+1) + 3$.

Step 5 :Substituting $g(n+1)$ into this equation, we get $h(g(n+1)) = 3((n+1)^{3}+5(n+1)) + 3$.

Step 6 :Expanding this equation, we get $h(g(n+1)) = 3n^{3} + 9n^{2} + 24n + 21$.

Step 7 :So, the final answer is \(\boxed{3 n^{3}+9 n^{2}+24 n+21}\).

From Solvely APP
Source: https://solvelyapp.com/problems/8102/

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