Step 1 :Solve this equation by factorising: \(y^{2}+3 y-10=0\)
Step 2 :We need to factor the quadratic equation and find the values of y that satisfy the equation.
Step 3 :\(y^2 + 3y - 10 = (y - 2)(y + 5)\)
Step 4 :Set each factor equal to zero: \((y - 2) = 0\) and \((y + 5) = 0\)
Step 5 :Solve for y: \(y = 2\) and \(y = -5\)
Step 6 :\(\boxed{y = 2, y = -5}\)