Step 1 :Calculate the F-statistic: \(F = \frac{590.49}{268.96} = 2.1955\)
Step 2 :Calculate the p-value: p-value = 0.0241
Step 3 :Compare p-value to significance level: 0.0241 < 0.05
Step 4 :\boxed{\text{Reject the null hypothesis. The varsity team is more consistent in scoring than the freshman team.}}