Find the probability $P\left(E^{C}\right)$ if $P(E)=0.23$. The probability $\mathrm{P}\left(\mathrm{E}^{\mathrm{C}}\right)$ is (Simplify your answer.)

Step 1 ：Given that the probability of event E, denoted as \(P(E)\), is 0.23

Step 2 ：The probability of the complement of event E, denoted as \(P(E^{C})\), is calculated by subtracting \(P(E)\) from 1

Step 3 ：Substitute \(P(E)\) into the equation, we get \(P(E^{C}) = 1 - P(E) = 1 - 0.23\)

Step 4 ：After calculating, we find that \(P(E^{C}) = 0.77\)

Step 5 ：Final Answer: The probability \(P\left(E^{C}\right)\) is \(\boxed{0.77}\)