Find the vertical and horizontal asymptotes of the function \(y = \frac{2x^2 - 3x + 1}{x - 1}\).

Step 1 ：First, simplify the function by dividing both the numerator and denominator by x. We get \(y = \frac{2x - 3 + \frac{1}{x}}{1 - \frac{1}{x}}\).

Step 2 ：As x approaches infinity, \(\frac{1}{x}\) approaches 0. Therefore, the function simplifies to \(y = \frac{2x - 3}{1}\), which is a straight line with a slope of 2 and a y-intercept of -3.

Step 3 ：The vertical asymptote is found by setting the denominator equal to zero and solving for x. So, \(x - 1 = 0\) gives x = 1.

Step 4 ：The horizontal asymptote is the line y = 2x - 3.