Step 1 :The vertex of a parabola given by the equation \(y = ax^2 + bx + c\) is at the point \((-b/2a, f(-b/2a))\).
Step 2 :For the given equation \(y = -x^2 + 3\), \(a = -1\) and \(b = 0\).
Step 3 :Substituting these values into the formula, we find that the x-coordinate of the vertex is \(0\).
Step 4 :Substituting \(x = 0\) into the equation, we find that the y-coordinate of the vertex is \(3\).
Step 5 :Therefore, the vertex of the parabola \(y = -x^2 + 3\) is \(\boxed{(0, 3)}\).