Step 1 :The period of a sine function is given by the formula \(2\pi/n\), where \(n\) is the coefficient of \(x\). In this case, \(n=3\).
Step 2 :So, the period of the function \(y=\sin 3x\) is \(2\pi/3\).
Step 3 :Final Answer: The period of the function \(y=\sin 3 x\) is \(\boxed{\frac{2\pi}{3}}\).