Find the average value of the function $f(x)=x^{2}-9$ on $[0,9]$ The average value of the function $f(x)=x^{2}-9$ on $[0,9]$ is

Step 1 ：The average value of a function \(f(x)\) on the interval \([a,b]\) is given by the formula: \[\frac{1}{b-a}\int_{a}^{b}f(x)dx\]

Step 2 ：We need to find the average value of the function \(f(x)=x^{2}-9\) on \([0,9]\).

Step 3 ：To do this, we compute the integral of \(f(x)\) from 0 to 9 and then divide by 9-0.

Step 4 ：The result of this calculation is 18.

Step 5 ：Final Answer: The average value of the function \(f(x)=x^{2}-9\) on \([0,9]\) is \(\boxed{18}\).