The function in the table is quadratic: \begin{tabular}{|l|l|} \hline & $f(x)$ \\ \hline-1 & -7 \\ \hline 0 & 1 \\ \hline 1 & 9 \\ \hline 2 & 17 \\ \hline \end{tabular} True False

Step 1 ：The function in the table is given as follows:

Step 2 ：\[\begin{tabular}{|l|l|} \hline & f(x) \\ \hline-1 & -7 \\ \hline 0 & 1 \\ \hline 1 & 9 \\ \hline 2 & 17 \\ \hline \end{tabular}\]

Step 3 ：We need to check if the function is quadratic. A function is quadratic if the differences between consecutive function values form a constant sequence. This is because the difference between consecutive function values of a quadratic function is a linear function, and the difference between consecutive function values of a linear function is a constant function.

Step 4 ：Let's calculate the differences between consecutive function values and check if they form a constant sequence.

Step 5 ：The function values are -7, 1, 9, 17. The differences between these values are 8, 8, 8.

Step 6 ：The second differences are all 0, which means the differences between consecutive function values form a constant sequence.

Step 7 ：Therefore, the function in the table is quadratic.

Step 8 ：Final Answer: \(\boxed{\text{True}}\)