Problem
$\frac{6 n}{n^{2}-9}-\frac{3}{n+3}$
Solution
Step 1 ：Factor the denominator of the first term: $\frac{6n}{(n-3)(n+3)} - \frac{3}{n+3}$
Step 2 ：Find a common denominator and simplify: $\boxed{\frac{3}{n-3}}$
Step 1 ：Factor the denominator of the first term: $\frac{6n}{(n-3)(n+3)} - \frac{3}{n+3}$
Step 2 ：Find a common denominator and simplify: $\boxed{\frac{3}{n-3}}$
