Question 6 of 29 There are 8 seniors on the high school soccer team. Two of them will be chosen to be co-captains. How many ways are there to choose the cocaptains? Decide if this is a permutation or a combination, and then find the number of ways to choose the co-captains. A. Permutation; number of ways $=56$ B. Combination; number of ways $=28$ C. Permutation; number of ways $=28$ D. Combination; number of ways $=56$

Step 1 ：This is a combination problem because the order of the co-captains does not matter. We need to find the number of ways to choose 2 co-captains from 8 seniors.

Step 2 ：Using the combination formula: \(C(n, k) = \frac{n!}{k!(n-k)!}\), where n = 8 and k = 2, we get \(C(8, 2) = \frac{8!}{2!(8-2)!} = \frac{8!}{2!6!}\)

Step 3 ：Calculating the factorials: \(8! = 8 \times 7 \times 6!\) and \(2! = 2\)

Step 4 ：Substituting the factorials into the combination formula: \(C(8, 2) = \frac{8 \times 7 \times 6!}{2 \times 6!}\)

Step 5 ：Simplifying the expression: \(C(8, 2) = \frac{8 \times 7}{2} = 4 \times 7 = 28\)

Step 6 ：\(\boxed{28}\)