Problem
Question 5 of 29 Suppose a normal distribution has a mean of 50 and a standard deviation of 3. What is $P(x \leq 47)$ ? A. 0.84 B. 0.16 C. 0.025 D. 0.975
Solution
Step 1 ：Calculate the z-score: $$z = \frac{x - \mu}{\sigma} = \frac{47 - 50}{3} = -1$$
Step 2 ：Find the probability from the z-table or CDF: $$P(x \leq 47) = P(z \leq -1) \approx 0.16$$
Step 3 ：\(\boxed{\text{Final Answer: B. 0.16}}\)
