Problem
A spinner has 10 equally sized sections, 7 of which are gray and 3 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue? Write your answer as a fraction in simplest form.
Solution
Step 1 ：\( P(G) = \frac{7}{10} \)
Step 2 ：\( P(B) = \frac{3}{10} \)
Step 3 ：\( P(G \cap B) = \frac{7}{10} \cdot \frac{3}{10} = \frac{21}{100} \)
