IQ scores are normally distributed with a mean of 100 and a standard deviation of 15 . Out of a randomly selected 1450 people from the population, how many of them would have an IQ between 106 and 125, to the nearest whole number?

Step 1 ：1. Calculate the z-scores for 106 and 125: \[ z_1 = \frac{106 - 100}{15} \approx 0.4 \] \[ z_2 = \frac{125 - 100}{15} \approx 1.67 \]

Step 2 ：2. Use a standard normal distribution table or calculator to find the area under the curve between z-scores \(z_1\) and \(z_2\): \[ P(0.4 \le Z \le 1.67) \approx 0.3944 \]

Step 3 ：3. Calculate the number of people with IQ between 106 and 125: \[ 1450 \times 0.3944 \approx 571.86 \]