Problem
In a system the mass is kept constant. The initial temperature of the system is \( 87.2^{\circ} \mathrm{C} \), the pressure is \( 57.3 \mathrm{~atm} \), and the volume is \( 3.8 \mathrm{~L} \). If the volume changes to \( 8.8 \mathrm{~L} \) and the pressure changes to \( 12.2 \mathrm{~atm} \) what is the temperature in degrees Celsius?
Solution
Step 1 ：\( P_1V_1/T_1 = P_2V_2/T_2 \)
Step 2 ：\( (57.3\mathrm{~atm})(3.8\mathrm{~L})/(87.2+273.15) = (12.2\mathrm{~atm})(8.8\mathrm{~L})/T_2 \)
Step 3 ：\( T_2 = 147.6432^{\circ} \mathrm{C} \)
