Problem
In a system the temperature and mass are kept constant. The initial pressure of the system is \( 6.27 \mathrm{~mm} \mathrm{Hg} \). If the pressure changes to 2.8 \( \mathrm{mm} \mathrm{Hg} \) when the volume changes to \( 0.765 \mathrm{~L} \) what was the original volume?
Solution
Step 1 ：1. Use Boyle's Law: \(P_1V_1=P_2V_2\)
Step 2 ：2. Solve for \(V_1\): \(V_1=\frac{P_2V_2}{P_1}\)
Step 3 ：3. Substitute values: \(V_1=\frac{(2.8 \mathrm{~mm} \mathrm{Hg})(0.765 \mathrm{~L})}{6.27 \mathrm{~mm} \mathrm{Hg}}\)
