Fill in the missing values to make the equations true. (a) $\log _{2} 7-\log _{2} 5=\log _{2} \square$ (b) $\log _{5} 11+\log _{5} \square=\log _{5} 44$ (c) $-2 \log _{2} 3=\log _{2} \square$

Step 1 ：Use the logarithm properties to solve these equations. The properties are as follows:

Step 2 ：1. \(\log_b{mn} = \log_b{m} + \log_b{n}\)

Step 3 ：2. \(\log_b{\frac{m}{n}} = \log_b{m} - \log_b{n}\)

Step 4 ：3. \(n\log_b{m} = \log_b{m^n}\)

Step 5 ：For equation (a), use the second property to combine the two logarithms on the left side of the equation. The equation then becomes \(\log_2{\frac{7}{5}} = \log_2{\square}\). The value that makes this equation true is \(\frac{7}{5}\).

Step 6 ：For equation (b), use the first property to combine the two logarithms on the left side of the equation. The equation then becomes \(\log_5{11 \times \square} = \log_5{44}\). The value that makes this equation true is \(\frac{44}{11}\).

Step 7 ：For equation (c), use the third property to rewrite the left side of the equation. The equation then becomes \(\log_2{3^{-2}} = \log_2{\square}\). The value that makes this equation true is \(3^{-2}\).

Step 8 ：Final Answer:

Step 9 ：(a) \(\boxed{1.4}\)

Step 10 ：(b) \(\boxed{4.0}\)

Step 11 ：(c) \(\boxed{0.1111111111111111}\)