Find the value of $z_{\alpha}$. \[ \alpha=0.12 \] The value of $z_{0.12}$ is (Round to two decimal places as needed.)

Step 1 ：Given that \(\alpha=0.12\), we are asked to find the z-score that corresponds to the 12th percentile in a standard normal distribution.

Step 2 ：We can use the inverse of the cumulative distribution function (CDF) to find this z-score, which returns the x-value that corresponds to a given percentile.

Step 3 ：After calculation, we find that \(z_{\alpha} = -1.1749867920660904\).

Step 4 ：Rounding to two decimal places as needed, we get \(z_{\alpha} = -1.17\).

Step 5 ：Final Answer: The value of \(z_{0.12}\) is \(\boxed{-1.17}\).