Problem

Show Intro/ Suppose that $f(x)=x^{2}+4 x-21$ a. Write $f(x)=x^{2}+4 x-21$ in factored form. \[ f(x)= \] Preview b. Determine the function's horizontal intercepts. Use a comma to separate your answers. \[ x= \] Preview

Solution

Step 1 :Suppose that the function is given by \(f(x)=x^{2}+4 x-21\).

Step 2 :To write the function in factored form, we need to factorize the quadratic equation \(x^{2}+4 x-21\). This can be done by finding two numbers that multiply to -21 (the constant term) and add to 4 (the coefficient of the x term).

Step 3 :The factored form of the function \(f(x)=x^{2}+4 x-21\) is \(f(x) = (x - 3)(x + 7)\).

Step 4 :The horizontal intercepts of a function are the x-values where the function equals zero. This can be found by setting the factored form of the function equal to zero and solving for x.

Step 5 :The function's horizontal intercepts are \(x = -7, 3\).

Step 6 :\(\boxed{f(x) = (x - 3)(x + 7)}\)

Step 7 :\(\boxed{x = -7, 3}\)

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Source: https://solvelyapp.com/problems/7684/

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